Question

A bag contains 8 hamburgers, 3 cheeseburgers and 10 chicken sandwiches. The probability of selecting a chicken sandwich, eating it, and then a selecting a hamburger is 4/21. What is the fraction (h) of "selecting a hamburger" after selecting a chicken sandwich and eating it

A. 2/21
B. 3/21
C. 4/21
D. 5/21

Answer 1

The fraction of selecting a hamburger after selecting a chicken sandwich and eating it is 7/21 or 1/3.

Step-by-step explanation:

To find the fraction of selecting a hamburger after selecting a chicken sandwich and eating it, we can use the given information about the probability. Let's break down the problem step by step:

1. The probability of selecting a chicken sandwich is 10/21 because there are 10 chicken sandwiches out of a total of 8 hamburgers, 3 cheeseburgers, and 10 chicken sandwiches.
2. After eating the chicken sandwich, there will be 7 hamburgers left in the bag.
3. So, the probability of selecting a hamburger from the remaining 7 hamburgers is 7/21.
4. Therefore, the fraction of selecting a hamburger after selecting a chicken sandwich and eating it is 7/21, which simplifies to 1/3.