Question

A car accelerates at a rate of 4m/s in 5 s. calculate the change of velocity​

Answer 1

The change of velocity for a car that accelerates at 4 m/s^2 over 5 seconds is calculated using the formula ∆v = a * ∆t, resulting in a change of velocity of 20 m/s.

Step-by-step explanation:

To calculate the change of velocity of a car that accelerates at a rate of 4 m/s2 over a period of 5 seconds, we can use the formula for acceleration, which is:

a = ∆v / ∆t

Where:

• a is the acceleration
• ∆v is the change of velocity (final velocity - initial velocity)
• ∆t is the change in time

We can rearrange this formula to solve for the change of velocity:

∆v = a * ∆t

Plugging in the known values:

• a = 4 m/s2
• ∆t = 5 s

We get:

∆v = 4 m/s

2

* 5 s = 20 m/s

Therefore, the change of velocity is 20 meters per second (m/s).