Question

Calculate the heat change in joules for condensation of 7.10 g of steam at 100∘C? . Express your answer as a positive value using three significant figures and include the appropriate units.

Answer 1

The heat change for the condensation of 7.10 g of steam at 100°C is calculated by multiplying the mass of the steam (7.10 g) with the heat of vaporization of water (2260 J/g), resulting in 16046 J.

Step-by-step explanation:

To calculate the heat change in joules for the condensation of 7.10 g of steam at 100°C, we can use the heat of vaporization of water. The heat of vaporization (enthalpy of vaporization) for water at 100°C is 2260 J/g. This is the amount of energy needed for 1 gram of water to convert from vapor to liquid at atmospheric pressure without temperature change.

We can use the formula:

Q = m x ΔHvap

Where:

• Q is the heat change
• m is the mass of the substance in grams
• ΔHvap is the heat of vaporization of water (2260 J/g)

By substituting the values:

Q = 7.10 g x 2260 J/g

Q = 16046 J

Therefore, the heat change for the condensation of 7.10 g of steam at 100°C is 16046 J, expressed as a positive value.