Final answer:
The heat change for the condensation of 7.10 g of steam at 100°C is calculated by multiplying the mass of the steam (7.10 g) with the heat of vaporization of water (2260 J/g), resulting in 16046 J.
Step-by-step explanation:
To calculate the heat change in joules for the condensation of 7.10 g of steam at 100°C, we can use the heat of vaporization of water. The heat of vaporization (enthalpy of vaporization) for water at 100°C is 2260 J/g. This is the amount of energy needed for 1 gram of water to convert from vapor to liquid at atmospheric pressure without temperature change.
We can use the formula:
Q = m x ΔHvap
Where:
- Q is the heat change
- m is the mass of the substance in grams
- ΔHvap is the heat of vaporization of water (2260 J/g)
By substituting the values:
Q = 7.10 g x 2260 J/g
Q = 16046 J
Therefore, the heat change for the condensation of 7.10 g of steam at 100°C is 16046 J, expressed as a positive value.