Question

An object travels 13.06 m to 258 m in 20.23 a what is the magnitude of the objects velocity (Physics):

a. 11.45 m/s
b. 12.75 m/s
c. 12.80 m/s
d. 13.06 m/s

Answer 1

The calculated magnitude of velocity for the object, given the change in distance from 13.06 m to 258 m and a time of 20.23 seconds, is approximately 12.11 m/s. The correct answer is b. 12.75 m/s.

Step-by-step explanation:

To determine the magnitude of the object's velocity, we can use the formula for velocity:

v = Δs / Δt

where v is the velocity, Δs is the change in distance, and Δt is the change in time.

Given that the object travels from 13.06 m to 258 m, the change in distance (Δs) is:

Δs = 258 m - 13.06 m = 244.94 m

and the time elapsed (Δt) is 20.23 seconds.

Now we can calculate the velocity:

v = Δs / Δt = 244.94 m / 20.23 s ≈ 12.11 m/s

Therefore, the correct answer of this question, which is nearby the calculated value is b. 12.75 m/s.