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What is the acceleration of a bicyclist who uniformly accelerates from rest to 7m/s and 4 s?

User Gian
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1 Answer

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Final answer:

The acceleration of a bicyclist who starts from rest and reaches a velocity of 7 m/s in 4 seconds is 1.75 m/s².

Step-by-step explanation:

The question is asking for the acceleration of a bicyclist who starts from rest and reaches a velocity of 7 m/s in 4 seconds.

Acceleration is defined as the change in velocity over time. To calculate this, we use the formula:

a = (v - u) / t

Where:
a is the acceleration,
v is the final velocity,
u is the initial velocity, and
t is the time taken to change velocity.

Since the bicyclist starts from rest, u = 0, v = 7 m/s, and t = 4 s. Plugging these values into the formula gives us:

a = (7 m/s - 0 m/s) / 4 s = 7/4 m/s² =

1.75 m/s²

.

Thus, the acceleration of the bicyclist is 1.75 m/s².

User Huantao
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