Final answer:
The acceleration of the elevator, induced by a 70 kg person exerting a force of 300 N, is calculated to be approximately 4.29 m/s² using Newton's second law, F = ma.
Step-by-step explanation:
To determine the acceleration of the elevator, the applied force can be analyzed using Newton's second law, F = ma, where F represents force, m denotes mass, and a stands for acceleration.
In this scenario, with a person weighing 70 kg exerting a force of 300 N on the elevator floor, the equation is formulated as 300 N = 70 kg * a. Solving for acceleration, a, yields a = 300 N / 70 kg, resulting in approximately 4.29 m/s².
This computation reveals that the elevator is experiencing an acceleration of 4.29 meters per second squared. The acceleration signifies the rate of change of velocity and is indicative of the elevator's upward or downward movement under the influence of the force applied by the person.
Understanding such physical principles aids in comprehending the dynamic interactions within the elevator system.