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What volume would a 0.521 gram sample of air occupy if the density of air is 1.09 g/L?

1 Answer

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Final answer:

The volume of a 0.521 gram sample of air, with a density of 1.09 g/L, is approximately 0.478 L.

Step-by-step explanation:

To find the volume of a sample of air, we can use the formula:

Volume = Mass / Density

In this case, the mass of the air sample is 0.521 grams and the density of air is 1.09 g/L.

Let's plug these values into the formula:

Volume = 0.521 g / 1.09 g/L

After dividing, we get a volume of approximately 0.478 L.