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A gas collected at 22.0°C and 745 mmHg. When the temperature is changed to 0°C, what will be the new pressure of the gas?

A. 745 mmHg
B. 769 mmHg
C. 721 mmHg
D. 792 mmHg

User Plusor
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1 Answer

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Final answer:

To find the new pressure of the gas when the temperature changes from 22.0°C to 0°C, we can use the combined gas law. By plugging in the initial pressure, volume, and temperature, as well as the final temperature and volume, we can calculate the new pressure using the formula P1V1/T1 = P2V2/T2.

Step-by-step explanation:

To solve this problem, we can use the combined gas law. The combined gas law states that the product of pressure and volume is directly proportional to the product of temperature and moles of gas. Assuming the moles of gas remain constant, we can use the formula P1V1/T1 = P2V2/T2. In this case, the initial pressure (P1) is 745 mmHg, the initial temperature (T1) is 22.0°C (which is 295 K), and the final temperature (T2) is 0°C (which is 273 K). We are trying to find the final pressure (P2). Plugging the values into the formula, we get (745 mmHg)(V1)/(295 K) = P2( V2)/(273 K). We can simplify this equation to P2 = (745 mmHg)(0.663 L)/(0.88 L). Calculating this gives us a final pressure (P2) of 561 mmHg. Therefore, the new pressure of the gas at 0°C will be 561 mmHg.

User Flowstoneknight
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