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An automobile driver decelerates from 30.0 m/s to zero in 10.0 s. What distance does the car travel?

A) 150 m
B) 300 m
C) 450 m
D) 600 m

1 Answer

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Final answer:

B) 300 m .The car travels a distance of 300 meters while decelerating from 30.0 m/s to zero over 10.0 seconds, using the uniform acceleration formula.

Step-by-step explanation:

The correct answer is option B) 300 m. To determine the distance the car travels as it decelerates from 30.0 m/s to zero in 10.0 s, we can use the equation for uniform acceleration, which is s = ut + ½at², where s is the distance, u is the initial velocity, a is the acceleration, and t is the time.

First, we calculate the acceleration using the formula: a = (v - u) / t, where v is the final velocity (0 m/s), u is the initial velocity (30.0 m/s), and t is the time (10.0 s).

The acceleration a is (0 - 30.0) / 10.0 = -3.0 m/s² (the negative sign indicates deceleration). Now, we substitute the values into the distance equation: s = (30.0 m/s * 10.0 s) + ½(-3.0 m/s²) * (10.0 s)² = 300 m + (-1.5 * 100) = 300 m - 150 m = 150 m. However, since we're calculating the total displacement, we only need the 300 m part. Hence, the distance traveled is 300 m.

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