Question

A sample of gas occupies a volume of 260.0 mL at 6.00°C and 203.9 kPa. What volume would the gas occupy at 38.0°C and 57.0 kPa? Make sure your answer is rounded to significant figures, and remember the temperature needs to be solved in Kelvin.

a) 150.8 mL
b) 310.2 mL
c) 397.6 mL
d) 500.3 mL

Answer 1

To solve this problem, use the combined gas law equation to calculate the final volume of the gas.

Step-by-step explanation:

To solve this problem, we will use the combined gas law equation, which relates the initial and final volumes, pressures, and temperatures of a gas:

V1/T1 = V2/T2

First, we need to convert the temperatures to Kelvin. To do this, we add 273.15 to each temperature: 6.00°C + 273.15 = 279.15 K, and 38.0°C + 273.15 = 311.15 K.

Next, we plug in the given values:

260.0 mL / 279.15 K = V2 / 311.15 K

Now, we can solve for V2:

V2 = (260.0 mL * 311.15 K) / 279.15 K = 290.80 mL

Since the question asks for the answer rounded to significant figures, the correct answer is 291 mL (rounded to three significant figures).