Final answer:
The coefficient of kinetic friction is calculated using the net force equation for a 3 kg block being pulled to the left with an 11N force and 3 m/s^2 acceleration. The coefficient is found to be approximately 0.02, which does not match any of the answer choices provided.
Step-by-step explanation:
The student is asking for assistance in calculating the coefficient of kinetic friction (μk). This can be found using Newton's second law, which states that the sum of all forces on an object equals its mass times its acceleration (Fnet = m × a). For a 3 kg block being pulled with a force of 11N and accelerating at 3 m/s2, we consider the forces acting on the block: the applied force (Fapplied), the frictional force (Ffriction), and the normal force (which equals the gravitational force due to the block's weight in this horizontal scenario).
The formula for the frictional force is Ffriction = μk × normal force. We know that Fnet = Fapplied - Ffriction. The normal force here is the weight of the block (mass × gravity), or 3 kg × 9.8 m/s2, which is approximately 29.4 N. Plugging in the known values, we have:
3 kg × 3 m/s2 = 11N - (μk × 29.4N)
Which simplifies to:
9N = 11N - (μk × 29.4N)
And after solving for μk
μk = (11N - 9N) / 29.4N
μk = 0.068 / 29.4N
μk ≈ 0.02
Here, the coefficient of kinetic friction is μk ≈ 0.02, which means none of the presented options (A, B, C, D) are correct.