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Given points (3,4) and (4,6), find the equation of the line containing these points.

User Suna
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Final answer:

To find the equation of the line passing through (3,4) and (4,6), we calculate the slope as 2 and then use the point-slope form to find the equation, which is y = 2x - 2.

Step-by-step explanation:

To find the equation of a line containing the points (3,4) and (4,6), first we calculate the slope (m) of the line using the formula:

m = (y2-y1)/(x2-x1)

Substituting the given points:

m = (6-4)/(4-3) = 2/1 = 2

Now that we have the slope, we use one of the points and the slope to write the equation in point-slope form, which is y - y1 = m(x - x1). Let's use point (3,4):

y - 4 = 2(x - 3)

Simplifying, we get the equation in slope-intercept form (y = mx + b):

y - 4 = 2x - 6

y = 2x - 2

Thus, the equation of the line is y = 2x - 2.

User Qinsheng Zhang
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