Final answer:
In an elastic collision where equal masses collide, object A and B will exchange velocities post-collision. Hence after the collision, A will move at 10 m/s in the -x-direction, while B will move at 20 m/s in the +x-direction.
Step-by-step explanation:
The subject of the question is a collision in Physics, specifically involving the conservation of momentum and possibly kinetic energy. If objects A and B of equal mass collide elastically, and prior to the collision object A is moving at 20 m/s in the +x-direction and object B at 10 m/s in the -x-direction, their final velocities can be determined using conservation of momentum and kinetic energy.
For an elastic collision, both momentum and kinetic energy are conserved. Let's assume the mass of each car is m. The total initial momentum is m * 20 m/s + (-m * 10 m/s) = 10m m/s. Since the collision is elastic, this will also be the total momentum after the collision.
Since the objects have equal mass and the collision is elastic, they will simply exchange velocities. Thus, after the collision, A will move at 10 m/s in the -x-direction, and B will move at 20 m/s in the +x-direction.