Final answer:
The total momentum of two hockey pucks in a closed system, where one is moving and the other is at rest, can be determined using the law of conservation of momentum. Without the mass of the pucks, it's impossible to select an option from A to D.
Step-by-step explanation:
The question asks us to determine the momentum of two hockey pucks in a closed system using the law of conservation of momentum. In such a system, total momentum before the collision must equal total momentum after the collision. Given one puck is traveling at 2 m/s and the other is at rest, and assuming the pucks have equal mass, the moving puck's momentum is the only momentum in the system initially.
Let's assume the mass of each puck is m. The momentum (p) of an object is the product of its mass (m) and velocity (v), so p = m * v. For the moving puck: p = m * 2 m/s. With no other information on mass, we can't calculate the numeric value. But the options provided suggest that momentum is expressed in kg m/s, we will choose the option that best fits the scenario.
The key here is that since the other puck is at rest, its initial momentum is 0 kg m/s. Hence, the total momentum before the collision is just that of the moving puck. After the collision, the total momentum must remain constant if no external forces acted upon the system. Therefore, the answer will be the initial momentum of the moving puck, which we haven't got a value for, so we can't select an option from A to D without the mass of the pucks.