Final answer:
To make the number 9,613,27 divisible by 6, the last digit must be replaced with an 8 since it will then be divisible by both 2 and 3, which are the requirements for divisibility by 6.
Step-by-step explanation:
The question asks us to type a digit that makes the number 9,613,27 divisible by 6. A number is divisible by 6 if it is both divisible by 2 and by 3. To be divisible by 2, a number must end in 0, 2, 4, 6, or 8. Our number ends in 7, so it fails the divisibility rule for 2 and is not divisible by 6 in its current state. If we were to change the 7 to an 8, the number would then end in an even digit and pass the first part of the test. To be divisible by 3, the sum of the digits must be divisible by 3. If we add 8 instead of 7 to the sum of the other digits, the total sum becomes 30, which is divisible by 3. Therefore, the correct digit to make 9,613,27 divisible by 6 is 8.