Question

What is the completely factored form of x⁴y – 4x²y – 5y?

y(x2 – 5)(x2 + 1)

y(x2 + 5)(x2 – 1)

(x2y – 5)(x2 + 1)

(x2y + 5)(x2 – 1)

Answer 1

The completely factored form of x⁴y – 4x²y – 5y is y(x² – 5)(x² + 1).

Step-by-step explanation:

The completely factored form of x⁴y – 4x²y – 5y is y(x² – 5)(x² + 1).

To factor this expression completely, we look for common factors and then factor the quadratic expressions. In this case, we can factor out a y from each term to get y(x⁴ – 4x² – 5). Then, we can factor the quadratic expression x⁴ – 4x² – 5 as (x² – 5)(x² + 1).