Question

Use elimination to solve: NN + ND = 500 5NN + 10ND = 3000​ a) NN = 100, ND = 400

b) NN = 200, ND = 300
c) NN = 300, ND = 200
d) NN = 400, ND = 100

Answer 1

To solve the system of equations using elimination, multiply the first equation by 5 and the second equation by -1 to eliminate the 'NN' variable. Solve for 'ND' and substitute the value back into either of the original equations to solve for 'NN'. The solution is NN = 400 and ND = 100, corresponding to option d.

Step-by-step explanation:

To solve the system of equations using elimination, we need to eliminate one of the variables. In this case, we can eliminate the variable 'NN' by multiplying the first equation by 5 and the second equation by -1. This will give us:

5NN + 5ND = 2500

-5NN - 10ND = -3000

Adding these two equations together, the 'NN' terms will be eliminated, and we will be left with:

-5ND = -500

Divide both sides of the equation by -5 to solve for 'ND':

ND = 100

Substitute the value of 'ND' back into either of the original equations to solve for 'NN':

NN + 100 = 500

NN = 400

Therefore, the solution is NN = 400 and ND = 100, which corresponds to option d.