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A bird, starting from the ground, begins flapping its wings and propels itself straight upward to achieve a velocity of 6 m/s at the top of its flight. Throughout the duration of its flight, it has an acceleration of 2 m/s2. How long will it take the bird to fly the total distance upward?

A: 1 second
B: 2 seconds
C: 3 seconds
D: 4 seconds

1 Answer

2 votes

Final answer:

Using the kinematic equation v = u + at, we find it takes 3 seconds for the bird to achieve a velocity of 6 m/s upward with an acceleration of 2 m/s^2. Therefore, the correct answer is C: 3 seconds.

Step-by-step explanation:

To determine how long it will take the bird to fly the total distance upward with an acceleration of 2 m/s2 to achieve a velocity of 6 m/s, we use the kinematic equation v = u + at, where 'v' is the final velocity, 'u' is the initial velocity (0 m/s since the bird starts from the ground), 'a' is the acceleration, and 't' is the time. Plugging in the values, we get 6 m/s = 0 + (2 m/s2 * t). Solving for 't' gives us t = 6 m/s / 2 m/s2 = 3 seconds.

To find the time it takes for the bird to fly the total distance upward, we can use the kinematic equation: vf = vi + at, where vf is the final velocity, vi is the initial velocity, t is the time, and a is the acceleration. Given that the final velocity is 6 m/s, the initial velocity is 0 m/s (since the bird starts from rest), and the acceleration is 2 m/s², we can solve for time:

t = (vf - vi) / a = (6 m/s - 0 m/s) / 2 m/s² = 3 seconds

Therefore, it will take the bird 3 seconds to fly the total distance upward.

Therefore, the correct answer is C: 3 seconds.

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