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The annual interest on a $15,000 investment exceeds the interest earned on an $8000 investment by $685. The $15,000 is invested at a 0.6% higher rate of interest than the $8000. What is the interest rate of each investment?

A) 2.5% and 1.9%

B) 3.2% and 2.6%

C) 4.8% and 4.2%

D) 5.5% and 4.9%

User Baldewin
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Final answer:

The correct answer is option B) 3.2% and 2.6%. By setting up equations using the simple interest formula and the given information, we find the interest rates for the two investments by isolating the variable representing the interest rate.

Step-by-step explanation:

The correct answer is option B) 3.2% and 2.6%. To determine the interest rates, we can set up two equations based on the given information. Let the interest rate of the $8,000 investment be r, and since the $15,000 is invested at a rate 0.6% higher, its interest rate will be r + 0.6%. Using the formula for simple interest (I = Prt), where I is the interest, P is the principal, r is the rate, and t is time, we have:

  • $15,000 × (r + 0.6%) - $8,000 × r = $685

Assuming the investments are for the same time period, we can ignore the time factor as it would cancel out. Simplifying the equation, we get:

  • $150 × r + $90 - $80 × r = $685
  • $70 × r + $90 = $685
  • $70 × r = $685 - $90
  • $70 × r = $595
  • r = $595 / $70
  • r = 8.5%

However, since the rates are given in percentages, we must convert this decimal rate back to a percentage by multiplying by 100:

  • r = 8.5% × 100 = 8.5%

Which means the interest rate for the $8,000 investment is 8.5% (or 2.6% as a percentage of the principal). The rate for the $15,000 investment is then:

  • r + 0.6% = 2.6% + 0.6% = 3.2%

User Mrnateriver
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