Question

If the perimeter of a triangle is equal to the perimeter of a square, and the triangle has sides of length 2x, 2x, and 5, while the square has sides of length 6x, what is the value of x?

A) x = 1

B) x = 2

C) x = 3

D) x = 4

Answer 1

After setting up an equation based on the perimeters of the given shapes, we found x = 1/4, which does not match any of the answer options. There may be a typo in the provided values.

Step-by-step explanation:

To find the value of x when the perimeter of a triangle equals the perimeter of a square, we need to set up an equation based on their perimeters. The perimeter of a triangle with sides of length 2x, 2x, and 5 is 4x + 5. The perimeter of a square with sides of length 6x is 24x. Setting these equal to each other:

• 4x + 5 = 24x

Now, we solve for x:

• 5 = 24x - 4x
• 5 = 20x
• x = 5 / 20
• x = 1/4

However, none of the provided options (A, B, C, D) match x = 1/4. This suggests there may be a typo within the question as presented.