103k views
0 votes
Using your knowledge of aspect ratios, find the difference between the actual screen area of an older analog TV with an aspect ratio of 4:3 and a newer high definition TV with an aspect ratio of 16:9, assuming both TVs have a measurement of 36 inches.

A) 432 sq inches
B) 192 sq inches
C) 576 sq inches
D) 336 sq inches

User Manthrax
by
8.0k points

1 Answer

0 votes

Final answer:

The actual screen area difference between an older analog TV and a newer high definition TV can be found by calculating the areas of both TVs. The difference in area is 486 sq inches.

Step-by-step explanation:

To find the difference between the actual screen area of an older analog TV with an aspect ratio of 4:3 and a newer high definition TV with an aspect ratio of 16:9, we need to calculate the areas of both TVs.

Let's start by finding the dimensions of each TV. For the older analog TV with a measurement of 36 inches, the width would be 36 inches and the height would be (36/4) * 3 = 27 inches. The area of this TV would be 36 * 27 = 972 square inches.

For the newer high definition TV with the same measurement of 36 inches, the width would be 36 inches and the height would be (36/16) * 9 = 81/2 = 40.5 inches. The area of this TV would be 36 * 40.5 = 1458 square inches.

The difference in the actual screen area between the two TVs is 1458 - 972 = 486 square inches. Therefore, the correct answer is 486 sq inches.

User Tony Liu
by
8.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories