Final answer:
The total milligrams of vitamin C in the salad can be calculated using the expression: Total vitamin C (in mg) = (300s + 200b + 42d), where 's' is the vitamin C content in mg/mL for spinach, 'b' for berries, and 'd' for dressing.
Step-by-step explanation:
To calculate the total amount of vitamin C in the salad, we need to consider the concentration of vitamin C in each ingredient and then sum them up. The spinach has s mg/mL of vitamin C, the berries have b mg/mL, and the dressing has d mg/mL. Since the salad contains 300 mL of spinach, 200 mL of berries, and 42 mL of dressing, the total vitamin C content can be calculated using the following expression:
Total vitamin C (in mg) = (300 mL × s mg/mL) + (200 mL × b mg/mL) + (42 mL × d mg/mL)
By simplifying, we find:
Total vitamin C (in mg) = (300s + 200b + 42d)
This expression represents the total milligrams of vitamin C in the salad.
For sample solution in the beginning of the experiment 20ml of sample was taken from 100ml of prepared solution containing 100mg of Ascorbic acid. As 49ml of iodine is required for the color change containing 20ml ascorbic acid solution, the dilution was done 5 times to that of the solution. Hence, the final volume of the iodine solution = 49× 5 = 245 ml
Mole iodine = Mass Ascorbic acid × 1 mole 176.12g of ascorbic acid × 1000ml volume of iodine M iodine = 0.1g × 1/176.12 × 1000 245ml = 0.00231 mol
For standard solution Mass Ascorbic acid = Mole iodine × Volume of iodine × 176.12 = 0.00231 × 45 × 176.12 = 91.54 mg Initially, the amount of Ascorbic acid was taken for 100mg and therefore for total amount of ascorbic acid i.e. 250 mg the ratio stands out to be 2.5 (250/100).