Question

A boy throws a ball up in the air with a velocity of 9 m/s when they are standing at the edge of a cliff 22 m high.

a) If the ball falls and lands at the base of the cliff, what is the velocity of the ball when it lands?

Answer 1

To determine the velocity of the ball when it lands, we can use the concept of projectile motion. First, we find the time it takes for the ball to reach the ground by solving the equation for height. Then, we calculate the velocity using the equation for velocity.

Step-by-step explanation:

To determine the velocity of the ball when it lands, we can use the concept of projectile motion. First, we need to find the time it takes for the ball to reach the ground. We can use the equation h = ut + (1/2)gt^2, where h is the height of the cliff (22 m), u is the initial velocity (9 m/s), g is the acceleration due to gravity (-9.8 m/s^2), and t is the time. Substituting the known values, we can solve for t. Once we have the value of t, we can substitute it into the equation v = u + gt to find the velocity of the ball when it lands.

Let's calculate the time it takes for the ball to reach the ground:

22 = 9t + (1/2)(-9.8)t^2

By solving this equation, we can find the value of t. Once we have t, we can calculate the velocity using v = u + gt:

v = 9 - 9.8t