Final answer:
The cash register contains 196 five dollar bills. We determined this by setting up a system of linear equations using the given total amount and the relationship between the numbers of five and fifty dollar bills.
Step-by-step explanation:
The question involves solving a system of linear equations to determine the number of five dollar bills and fifty dollar bills in a cash register. The total amount of money is given as $3,430, with the number of five-dollar bills being four times the number of fifty-dollar bills.
Let's denote the number of fifty-dollar bills as x and the number of five-dollar bills as 4x. Since each fifty-dollar bill is worth $50, for the x fifty-dollar bills in the register, the total value is $50x. Similarly, for the 4x five-dollar bills, the total value is $5(4x) or $20x. Combined, the total value is $50x + $20x, which equals the total amount in the cash register, $3,430.
Adding the values of $50x and $20x together, we get:
$50x + $20x = $3,430
Simplify the equation by combining like terms:
$70x = $3,430
Divide both sides of the equation by $70 to find the value of x:
x = $3,430 / $70
x = 49
Now that we have the value of x, the number of fifty-dollar bills, we can find the number of five-dollar bills:
4x = 4 × 49
4x = 196
So, there are 196 five-dollar bills in the cash register.