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The density of a metal is 11.35g/ml. If 15.44 g of the metal is added to a 75.0ml graduated cylinder that contains 3.4 ml of water, what will be the final volume reading in the cylinder?

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Final answer:

To find the final volume reading after adding metal to water in a graduated cylinder, calculate the volume of the metal using its density and mass, then add this volume to the initial volume of water. The volume of metal is found by dividing its mass by its density. Finally, add the volume of the metal to the initial volume in the cylinder to get the final volume reading.

Step-by-step explanation:

The question presents a scenario in which the density of a metal is given, and the metal is added to water in a graduated cylinder. To find the final volume reading after submerging the metal in the water, we employ our understanding of density (ρ = m/V), mass (m), and volume (V).

The density formula is rearranged to solve for volume (V = m/ρ).

Firstly, we calculate the volume of the metal:
Vmetal = mmetal/ρmetal

Using the given density (11.35 g/ml) and the mass of the metal (15.44 g):
Vmetal = 15.44 g / 11.35 g/ml ≈ 1.36 ml

To find the final volume in the graduated cylinder, we add the initial volume of water to the volume of the metal:
Vfinal = Vwater + Vmetal
Vfinal = 3.4 ml + 1.36 ml ≈ 4.76 ml

However, we must consider the initial volume of water plus the addition of metal for the final volume reading. The correct final volume is:
Vfinal = 75.0 ml + 1.36 ml ≈ 76.36 ml.

It is important to keep in mind the significant figures when presenting the final volume. The given figures suggest that we should round our answer to the nearest tenths place, resulting in a final volume reading of 76.4 ml.

User Mike Nitchie
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