Final answer:
The gigabyte will reach a height of 25.6 meters. Using the kinematic equation for motion under uniform acceleration, the object kicked straight up at a speed of 22.4 m/s will reach a maximum height of 25.6 meters before beginning to fall back down due to gravity.
Step-by-step explanation:
To determine how high the gigabyte will go, we can use the laws of projectile motion. When an object is thrown straight up, it will follow a parabolic path and eventually reach its highest point before falling back down due to gravity.
The formula to calculate the maximum height reached is h = (v^2) / (2g), where h is the height, v is the initial velocity, and g is the acceleration due to gravity. Plugging in the given values, we have h = (22.4 m/s)^2 / (2 * 9.8 m/s^2) = 25.6 meters.
Therefore, the gigabyte will reach a height of 25.6 meters.
Using the kinematic equation for motion under uniform acceleration, the object kicked straight up at a speed of 22.4 m/s will reach a maximum height of 25.6 meters before beginning to fall back down due to gravity.
To calculate how high the object (in this case, humorously referred to as a gigabyte, but presumably meant to be a physical object like a ball or shot put) goes when kicked straight up at a speed of 22.4 m/s, we use the kinematic equation for motion under uniform acceleration, with the acceleration due to gravity acting in the opposite direction of the initial velocity. Given that the acceleration due to gravity is -9.80 m/s², we can use the following equation, where v2 = u2 + 2as (v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement):
0 = (22.4 m/s)² + 2(-9.80 m/s²)(s)
Solving for s, the maximum height reached, we will find:
s = (22.4 m/s)² / (2 × 9.80 m/s²)
s = 25.6 m
So the object will reach a maximum height of 25.6 meters above the point of release before it starts to fall back down due to gravity.