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A pile of sand is cone-shaped. If the radius of the base is 5 feet and the altitude is 11 feet 2 inches, how many cubic feet of sand is in the pile? Round to the nearest tenth as needed.

Use π = 3.14
1 foot = 12 inches

1 Answer

6 votes

Final answer:

The volume of the cone-shaped pile of sand is approximately 367.53 cubic feet.

Step-by-step explanation:

The volume of the cone-shaped pile of sand can be calculated using the formula \(V = \frac{1}{3}\pi r^2 h\), where \(r\) is the radius of the base and \(h\) is the altitude. In this case, the radius is 5 feet and the altitude is 11 feet 2 inches. To convert the altitude to feet, we can use the fact that 1 foot is equal to 12 inches. So the altitude in feet is \(11 + \frac{2}{12} = 11.166\) feet. Now we can plug in the values into the formula: \[V = \frac{1}{3} \times 3.14 \times 5^2 \times 11.166 \approx 367.53 \text{ cubic feet}\]

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