Final answer:
The supply voltage needed for a 500W, 5 ohm load is 50 volts, calculated using the power formula and Ohm's law.
Step-by-step explanation:
To determine the value of the supply voltage for a 500W, 5 ohm load, we can use the power formula relevant to electric circuits. This formula is P = I2R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms. Since power (P) and resistance (R) are given, we must first solve for current (I) and then use the relationship between current, voltage, and resistance to find the supply voltage (V), which can be expressed as V = IR.
Firstly, rearrange the power formula to solve for current I = √(P/R). Substituting the known values gives I = √(500/5) = √100 = 10 A. Now, using the Ohm's law V = IR, we can calculate the supply voltage. V = 10 A * 5 Ω = 50 V. Thus, the supply voltage needed for a 500W, 5 ohm load is 50 volts.
To determine the supply voltage (V) for a 500W, 5-ohm load, Ohm's Law can be applied:
�
=
�
2
/
�
P=V
2
/R. Given the power (P) as 500W and the resistance (R) as 5 ohms, the equation becomes
500
=
�
2
/
5
500=V
2
/5. Solving for V, we find
�
=
500
×
5
=
50
V=
500×5
=50 volts. Therefore, the supply voltage required to deliver 500W of power to a 5-ohm load is 50 volts. This calculation stems from the fundamental relationship between power, voltage, and resistance in electrical circuits. Ohm's Law is a crucial tool in analyzing and designing electrical systems, providing a foundational understanding of the interplay between these key parameters. In this case, it facilitates the determination of the necessary voltage to achieve the specified power output across a given resistance.