Final answer:
The probability of picking Sprite fourth and Cherry Coke fifth without replacement is the product of the individual probabilities for each event, but the exact probability cannot be determined without knowing the total number of drinks available at the start.
Step-by-step explanation:
The question is asking for the probability of selecting a Sprite on the fourth pick and a Cherry Coke on the fifth pick without replacement from a set of options. To determine this probability, start by considering the chances of selecting a Sprite on the fourth pick. If there is one Sprite in a collection of n drinks, the probability of picking the Sprite on the fourth pick is 1/(n-3), because three drinks have already been picked without replacement.
Then, you need to calculate the probability of selecting the Cherry Coke after the Sprite has been picked, which would be 1/(n-4), as there are (n-4) drinks left.
The combined probability of both events happening in sequence would be the product of the two individual probabilities, assuming each pick is independent (once the Sprite is picked, it no longer affects the probability of picking the Cherry Coke).
Without the exact number of drinks to start with, we cannot calculate the precise probability; the correct answer would depend on that critical piece of information. The answer would be the product of the individual probabilities for each event, for example P(Sprite on 4th) × P(Cherry Coke on 5th).