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At what distance in air from a charge of +35μC would the magnitude of electric field strength be 15,000 N/C?

A) 0.002 m
B) 0.015 m
C) 0.06 m
D) 0.15 m

User Monacraft
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1 Answer

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Final answer:

The distance from a charge of +35µC at which the electric field strength would be 15,000 N/C is approximately 0.15 meters, corresponding to answer choice D.

Step-by-step explanation:

You want to determine the distance from a charge of +35µC at which the electric field strength is 15,000 N/C. The electric field (E) due to a point charge (q) in vacuum is given by Coulomb's law, expressed as E = k * |q| / r2, where k is Coulomb's constant (8.9875 × 109 Nm2/C2), |q| is the magnitude of the charge, and r is the distance from the charge.

To find the distance (r), you rearrange the formula to solve for r: r = √(k * |q| / E). Plug in the values: r = √((8.9875 × 109 * 35 × 10-6) / 15,000 ) which results in r being approximately 0.15 meters. So, the correct answer is D) 0.15 m.

User Paulo Guedes
by
8.2k points
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