Question

Given y1 = 11x − 5 and y2 = 6x + 5, when does y1 exceed y2 by 5?

a) x = 1
b) x = 2
c) x = 3
d) x = 4

Answer 1

To find when y1 exceeds y2 by 5, set up the equation 11x - 5 = 6x + 5 + 5 and solve for x. The correct answer is c) x = 3.

Step-by-step explanation:

To find the value of x when y1 exceeds y2 by 5, we need to set up an equation and solve for x. The equation would be:

11x - 5 = 6x + 5 + 5

Combining like terms, we get:

5x = 15

Dividing both sides by 5, we find that x = 3.

Therefore, the correct answer is c) x = 3.

The student asked when y1 exceeds y2 by 5. To find the answer, we set up the equation y1 - y2 = 5 and substitute the given expressions for y1 and y2.

11x - 5 - (6x + 5) = 5

Which simplifies to:

11x - 5 - 6x - 5 = 5

5x - 10 = 5

5x = 15

x = 3

Therefore, y1 exceeds y2 by 5 when x = 3, which corresponds to option (c).