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Teresa, Ahmad, and Goran served a total of 82 orders Monday at the school cafeteria. Goran served 2 times as many orders as Ahmad. Teresa served 6 fewer orders than Ahmad. How many orders did they each serve?

A) Ahmad: 24, Teresa: 18, Goran: 40
B) Ahmad: 20, Teresa: 22, Goran: 40
C) Ahmad: 26, Teresa: 20, Goran: 36
D) Ahmad: 22, Teresa: 16, Goran: 44

1 Answer

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Final answer:

Ahmad served 22 orders, Teresa served 16 orders, and Goran served 44 orders on Monday at the school cafeteria (option D is the correct answer).

Step-by-step explanation:

To solve the question, let's define some variables for the number of orders each person served:
Ahmad = A,
Teresa = T = A - 6 (since Teresa served 6 fewer orders than Ahmad),
Goran = G = 2A (since Goran served 2 times as many orders as Ahmad).

The total number of orders served by the three is 82, which gives us the equation:
A + T + G = 82,
Substitute T and G to get:
A + (A - 6) + 2A = 82,
Simplify and solve for A:
4A - 6 = 82,
4A = 88,
A = 22.

So Ahmad served 22 orders. Now find out the number of orders Teresa and Goran served:
T = 22 - 6 = 16,
G = 2 × 22 = 44.

Therefore, the correct answer is Ahmad: 22 orders, Teresa: 16 orders, Goran: 44 orders, which corresponds to option D.

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