Question

Find the percent error in a measurement of the boiling point of bromine if the laboratory figure is 40.6°C, and the accepted value is 59.35°C.

A. 31.61%
B. 45.57%
C. 68.39%
D. 74.06%

Answer 1

To find the percent error in a measurement, you can use the formula:

\[ \text{Percent Error} = \left| \frac{\text{Experimental Value} - \text{Accepted Value}}{\text{Accepted Value}} \right| \times 100\% \]

For the boiling point of bromine:

\[ \text{Percent Error} = \left| \frac{40.6 - 59.35}{59.35} \right| \times 100\% \]

Calculating this gives:

\[ \text{Percent Error} = \left| \frac{-18.75}{59.35} \right| \times 100\% \approx 0.3161 \times 100\% \approx 31.61\% \]

So, the correct answer is A) 31.61%.

Answer 2

The percent error in the measurement of the boiling point of bromine is calculated using the formula (|Experimental Value - True Value| / True Value) x 100%. The calculated percent error is approximately 31.61%, which is option A.

Step-by-step explanation:

To find the percent error in a measurement, you use the formula: Percent Error = (|Experimental Value - True Value| / True Value) × 100%. In this case, the experimental value is the laboratory figure (40.6°C), and the true value is the accepted boiling point of bromine (59.35°C).

Calculating the absolute difference: |40.6°C - 59.35°C| = 18.75°C.

Now, calculating the percent error: (18.75°C / 59.35°C) × 100% ≈ 31.61%.

Therefore, the percent error of the measurement is 31.61%, which corresponds to option A.