Question

A chemist mixes 425 milliliters of a solution that is 5% acid with 200 milliliters of a solution that is 55% acid.

(a) How many milliliters of acid are in the resulting mixture?
A.88 milliliters
B.285 milliliters
C.301 milliliters
D.245 milliliters

(b) What percentage of the resulting mixture is acid?
A.19.1%
B.24.7%
C.15.3%
D.22.4%

Answer 1

The amount of acid in the resulting mixture is 131 mL, and the percentage of acid is 20.96%.

Step-by-step explanation:

To find the amount of acid in the resulting mixture, we need to calculate the amount of acid in each solution and then add them together. In the 5% acid solution:

Amount of acid = 5% x 425 mL = 0.05 x 425 mL = 21.25 mL

In the 55% acid solution:

Amount of acid = 55% x 200 mL = 0.55 x 200 mL = 110 mL

Therefore, the total amount of acid in the resulting mixture is 21.25 mL + 110 mL = 131.25 mL, which can be rounded to 131 mL.

To find the percentage of acid in the resulting mixture, divide the amount of acid by the total volume of the mixture and multiply by 100%:

Percentage of acid = (131 mL / (425 mL + 200 mL)) x 100% = (131 mL / 625 mL) x 100% = 20.96%