Final answer:
Option a is correct, as the sum of interior angles of a triangle is always 180°, which can be demonstrated using parallel lines and alternate interior angles.
Step-by-step explanation:
The correct answer is option a, the sum is 180°. To prove that the sum of the interior angles of ΔABC is 180°, imagine drawing a line parallel to one of the triangle's sides passing through the opposite vertex. By alternate interior angles, the angles of the triangle are congruent to the angles created between the parallel lines and the transversal. The sum of the angles on a straight line is 180°, so the sum of the interior angles of the triangle must also be 180°.
In a triangle, the sum of the interior angle measures is always 180 degrees. This is a fundamental property of triangles.
For example, if we consider the given triangle ABC, we can calculate the sum of its interior angle measures as follows:
Angle 1 = 30.1°
Angle 2 = 48.7°
Angle 3 = 180° - (Angle 1 + Angle 2)
Angle 3 = 180° - (30.1° + 48.7°) = 101.2°
Therefore, the sum of the interior angle measures of triangle ABC is 30.1° + 48.7° + 101.2° = 180°.