Question

An airplane starts from rest and accelerates at a constant 3.73 m/s² for 35.48 s before leaving the ground. What is its displacement during this time?

a) 2637.27 m
b) 3456.94 m
c) 6612.46 m
d) 4783.79 m

Answer 1

The displacement of the airplane during the given time is 2358.92 m.

Step-by-step explanation:

To calculate the displacement of the airplane, we can use the formula:

displacement = 0.5 * acceleration * time^2

Plugging in the given values, we have:
displacement = 0.5 * 3.73 m/s² * (35.48 s)^2
displacement = 0.5 * 3.73 m/s² * 1261.4304 s²
displacement = 2358.9207 m
Therefore, the displacement of the airplane during this time is 2358.92 m.