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A car slows down from 26 m/s to rest in a distance of 82 m. What was its acceleration, assumed constant?

A) -2.64 m/s²
B) -0.64 m/s²
C) -0.32 m/s²
D) -1.32 m/s²

1 Answer

3 votes

Final answer:

The car's acceleration is -2.68 m/s².

Step-by-step explanation:

To find the acceleration of the car, we can use the formula:

Acceleration (a) = (final velocity^2 - initial velocity^2) / (2 * distance)

Given that the initial velocity (u) is 26 m/s and the final velocity (v) is 0 m/s, and the distance (d) is 82 m, we can substitute these values into the formula:

a = (0^2 - 26^2) / (2 * 82) = -2.68 m/s²

Therefore, the car's acceleration is -2.68 m/s².

User Kingkode
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