Question

A mass spring system is in SHM in the horizontal direction. If the mass is 0.25 kg, the spring constant is 12 N/m, and the amplitude is 15 cm,

a) What is the maximum speed of the mass?
A) 1.01 m/s
B) 0.75 m/s
C) 1.5 m/s
D) 0.5 m/s

Answer 1

The maximum speed of the mass in the given mass spring system is approximately 0.78 m/s.

Step-by-step explanation:

To find the maximum speed of the mass in a mass spring system in simple harmonic motion (SHM), you can use the equation:

v_max = A * √w

where A is the amplitude and √w is the angular frequency.

Given that the amplitude is 15 cm (0.15 m) and the spring constant is 12 N/m, we can calculate the angular frequency as follows:

√w = √(k/m)

Substituting the values, we have √w = √(12/0.25) = √(48) = 4√3.

Finally, substituting the values of amplitude and angular frequency into the equation, we get:

v_max = 0.15 * 4√3 ≈ 0.78 m/s

Therefore, the correct answer is A) 0.78 m/s.