Question

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.7 Mbps. The complete list of 50 data speeds has a mean of 18.12 Mbps and a standard deviation of 32.87 Mbps. Convert the carrier’s highest data speed to a z score.

Answer 1

To convert the carrier's highest data speed to a z-score, use the formula z = (X - μ) / σ, where X is the value we want to convert, μ is the mean, and σ is the standard deviation. In this case, the highest data speed is 76.7 Mbps, the mean is 18.12 Mbps, and the standard deviation is 32.87 Mbps. Plugging these values into the formula, the z-score is 1.78.

Step-by-step explanation:

To convert the highest data speed to a z-score, we use the formula: z = (X - μ) / σ, where X is the value we want to convert, μ is the mean, and σ is the standard deviation. In this case, the highest data speed is 76.7 Mbps, the mean is 18.12 Mbps, and the standard deviation is 32.87 Mbps. Plugging these values into the formula, we get z = (76.7 - 18.12) / 32.87 = 1.78. Therefore, the carrier's highest data speed has a z-score of 1.78.