Final answer:
The time taken by Superman to reach a scene after accelerating from 8.00 m/s to 7,930.23 m/s can be calculated using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken. By substituting the given values into the equation, we find that the time taken is approximately 4.13 seconds. Option E is correct.
Step-by-step explanation:
To calculate the time taken by Superman to reach a scene after accelerating from 8.00 m/s to 7,930.23 m/s with an acceleration of 187.1 m/s², we can use the equation:
v = u + at
Where:
v is the final velocity (7,930.23 m/s)
u is the initial velocity (8.00 m/s)
a is the acceleration (187.1 m/s²)
t is the time taken
Rearranging the equation and substituting the given values:
t = (v - u) / a
t = (7,930.23 m/s - 8.00 m/s) / 187.1 m/s²
t = 773.23 / 187.1 s
t = 4.13 s
Therefore, the time taken by Superman to reach the scene is approximately 4.13 seconds (option E).