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Andrew deposited $600 into his savings account with a compound interest of 3% after 48 months. What will be the balance in his account?

a. $669.72
b. $709.82
c. $730.56
d. $820.00

User JacoSolari
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1 Answer

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Final answer:

To find the balance in Andrew's savings account after 48 months with compound interest, use the formula A = P(1 + r/n)^(nt). Plugging in the values, the balance will be $675.30.

Step-by-step explanation:

To find the balance in Andrew's savings account after 48 months, we can use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:

  • A is the balance in the account
  • P is the principal (initial deposit)
  • r is the annual interest rate (as a decimal)
  • n is the number of times interest is compounded per year
  • t is the number of years

In this case, Andrew deposited $600, so P = 600. The annual interest rate is 3% or 0.03, so r = 0.03. The interest is compounded annually, so n = 1. The number of years is 48/12 = 4, so t = 4.

Plugging in these values into the formula, we get:

A = 600(1 + 0.03/1)^(1*4) = 600(1 + 0.03)^4 = 600(1.03)^4 = 600(1.1255) = 675.30

Therefore, the balance in Andrew's account after 48 months will be $675.30.

User Lanza
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