Question

A particle of mass 6 kg is acted upon by a force R = (ai + 10j) N on a bearing of 300 degrees. What is the magnitude of R?

A. a
B. 10
C. sqrt(a² + 10²)
D. a + 10

Answer 1

The magnitude of the force is given by the formula F = √(a² + b²), where a is the x-component of the force and b is the y-component of the force. In this case, a = a and b = 10. Therefore, the magnitude of the force is √(a² + 10²), which corresponds to option C.

Step-by-step explanation:

The magnitude of force is given by the formula F = √(a² + b²), where a is the x-component of the force and b is the y-component of the force. In this case, a = a and b = 10. Therefore, the magnitude of the force is √(a² + 10²), which corresponds to option C. So, the correct answer is C. sqrt(a² + 10²).