37.5k views
3 votes
How many grams of the element phosphorus are in a 0.78 mole sample of phosphorus?

User Slicekick
by
8.4k points

1 Answer

1 vote

Final answer:

To find the mass of phosphorus in a 0.78 mole sample, multiply the number of moles by the molar mass of phosphorus (30.97 g/mol), resulting in approximately 24.16 grams of phosphorus.

Step-by-step explanation:

To calculate the amount of phosphorus in grams for a 0.78 mole sample of phosphorus, we need to use the molar mass of phosphorus. The molar mass of phosphorus (P) is approximately 30.97 grams per mole. We can set up the calculation as follows:

  • Determine the molar mass of phosphorus: 30.97 g/mol
  • Multiply the number of moles by the molar mass: 0.78 moles × 30.97 g/mol
  • Calculate the mass in grams: Mass = 0.78 × 30.97 = 24.1566 grams

Therefore, a 0.78 mole sample of phosphorus contains approximately 24.16 grams of phosphorus.

User RGML
by
7.3k points