Question

A student placed 15.5 g of glucose (C₆H₁₂O₆) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 50.0 mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution?

Answer 1

To find the mass of glucose in 100 mL of the final diluted solution, calculate the amount of glucose in the original volume, then use the conservation of mass to determine the mass of glucose after dilution. The final amount of glucose in 100 mL of the solution is 1.55 grams.

Step-by-step explanation:

Calculating Mass of Glucose in Diluted Solution

To find the mass of glucose in 100 mL of the final solution, we need to understand the concept of serial dilutions and use the principle of conservation of mass. Initially, 15.5 g of glucose is dissolved to make 100 mL of solution. From this solution, a 50.0 mL sample is further diluted to 0.500 L (500 mL).

Step 1: Calculate the mass of glucose in 50 mL of the original solution. As 100 mL contains 15.5 g, 50 mL will contain half that amount which is 7.75 g.

Step 2: Since the mass of glucose will not change upon dilution, the 7.75 g is now distributed throughout 500 mL of solution after dilution.

Step 3: To find out how much glucose is in 100 mL of the final solution, we perform a simple proportion. If 500 mL contains 7.75 g, then 100 mL will contain one-fifth of 7.75 g, which is 1.55 g.