Final answer:
For every 22 cars parked in the De Anza parking garage, on average 8.25 cars are parked crookedly, based on a 37.5% rate. To determine the probability of at least 10 cars being parked crookedly, we would use a binomial distribution or a similar statistical method, though the question does not provide enough information to confirm the correct probability value.
Step-by-step explanation:
To determine how many cars parked in the De Anza parking garage are parked crookedly on average, we will utilize the given percentage of 37.5%. Since we're looking at 22 randomly surveyed cars, we calculate 8.25 by multiplying 22 by 0.375 (37.5%). Therefore, the correct answer to the first question is A) 8.25.
For the second question, the calculation of probability that at least 10 of the 22 cars are parked crookedly would typically involve using a binomial distribution or normal approximation to binomial, taking into account the probability of success (parking crookedly) on each trial (each car), the number of trials (22 cars), and the number of successes (at least 10 cars parked crookedly). As for the provided answers, without the exact binomial probabilities, we cannot confirm which of the given options is correct. An exact probability calculation would require more computational work including a formula or statistical software.