Question

The specific heat of gold is 0.126 J/gºC. How much energy is released

when a 350 g sample of gold is cooled from 88.5°C to 24.6°C?

Answer 1

Step-by-step explanation:

Specific heat capacity of gold (S)

= 0.126 J /kg°C

mass (m) = 350 g = 0.35 kg

difference in temperature (dt)

= 88.5°C - 24.6°C

= 63.9° C

Now

Energy released (Q)

= m*s*dt

= 0.35 * 0.126 * 63.9

= 2.81799 Joule

Hope it will help :)