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A six-sided fair die and an eight-sided fair die are rolled together. What is the probability of getting numbers whose sum is a multiple of 3? A 1/18 B 1/4 C 1/3 D 4/9 E 2/3​

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5 votes

Answer:

C 1/3

Explanation:

The numbers on a 6-sides die are 1, 2, 3, 4, 5, 6.

The number of an 8-sided die are 1, 2, 3, 4, 5, 6, 7, 8.

All the possible sums are:

2, 3, 4, 5, 6, 7, 8, 9,

3, 4, 5, 6, 7, 8, 9, 10,

4, 5, 6, 7, 8, 9, 10, 11,

5, 6, 7, 8, 9, 10, 11, 12

6, 7, 8, 9, 10, 11, 12, 13

7, 8, 9, 10, 11, 12 ,13, 14

The multiples of 3 are shown in bold and italic.

There are 48 possible sums.

16 sums are multiples of 3.

p(numbers whose sum is a multiple of 3) =

(number of outcomes that are multiples of 3)/(total number of possible outcomes)

p(numbers whose sum is a multiple of 3) = 16/48

p(numbers whose sum is a multiple of 3) = 1/3

Answer: C 1/3

User James White
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