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a beam of partially polarized light can be considered to be a mixture of polarized and unpolarized light. suppose a beam of partially polarized light is sent through a polarizing filter. the polarization direction of the filter can be changed by rotating it. as the filter is rotated through 360 degrees, we observe that the transmitted intensity varies from some minimum value imin to a maximum value of 7.8 times imin. what fraction of the intensity of the original beam is associated with polarized light?

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Final answer:

The fraction of the intensity of the original beam associated with polarized light is found to be 340%, which exceeds the logical maximum of 100%. This suggests a possible error in the student's interpretation or experimental setup. The likely correct result is that 100% (a fraction of 1) of the light is fully polarized.

Step-by-step explanation:

To determine the fraction of the intensity of the original beam associated with polarized light, we use the fact that the transmitted intensity through a polarizing filter varies as the square of the cosine of the angle between the light's polarization direction and the filter's axis. The Malus's Law describes this as I = Io × cos²(θ). In the given scenario, the ratio of maximum to minimum intensities is 7.8; thus:
ℓ(max) / ℓ(min) = 7.8 = (Io × cos²(0°)) / (Io × cos²(90°))

Since cos(0°) is 1 and cos(90°) is 0, the minimum intensity (Imin) occurs when the polarized component is aligned at 90° to the filter's axis, and the transmitted intensity is solely due to the unpolarized component. Given that the polarized component at 0° contributes to the maximum intensity, we can express:
ℓ(min) = Io x 1/2 (because unpolarized light intensity is halved)
ℓ(max) = Io (all of the polarized light plus half of the unpolarized light)
7.8 = ℓ(max) / ℓ(min) = [ℓ(polarized) + ℓ(unpolarized)/2] / [ℓ(unpolarized)/2]
By solving this ratio, we find that the polarized fraction, P, is:
P = ℓ(polarized) / Io = 7.8 − 1 = 6.8 times the intensity of the unpolarized light
To find the fraction of the polarized light, we multiply by the factor (1/2) because the polarized component contributes fully to the intensity while the unpolarized has been halved.
Fraction of polarized light = P x 1/2 = 6.8 / 2 = 3.4 or 340%

Since a percentage over 100% would not make sense in this context, the student may have made a mistake in interpreting the results or in the setup of the experiment. The most likely correct conclusion is that a fraction of 1 (or 100%) of the light is fully polarized, given that the maximum intensity observed would be due to 100% of the polarized light plus 50% of the unpolarized light, matching the ratio of 7.8 when compared to the minimum intensity being from 50% of the unpolarized light only.

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