Question

The perimeter of a rectangle is 50 centimeters. If the width of the rectangle is 9 centimeters

less than the length, find the dimensions of the rectangle.
Yes

Answer 1

Length = 17 cm

Width = 8 cm

Explanation:

Let the length be x cm

Therefore, Width = (x - 9) cm

Perimeter of rectangle = 2(l +w)

50 = 2[x + (x - 9)]

50/2 = 2x - 9

25 = 2x - 9

25+ 9 = 2x

2x = 34

x = 34/2

x = 17 cm

x - 9 = 17 - 9 = 8 cm

Therefore,

Length = 17 cm

Width = 8 cm

Thus, the dimensions of the rectangle are 17 cm and 8 cm.