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37 votes
Part A

Write an expression for the speed of Luna I in kilometers/minute. Represent this expression as a quotient of two numbers expressed in scientific notation.

User CuriousLearner
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2 Answers

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13 votes

The distance between Earth and the moon is 3.8 x 10^3 Kilometers. The time taken to travel this distance was 2.1 x 10^3 Minutes.

The formula to calculate speed is Speed = distance/time.

So, the speed of Luna I was 3.6 x 10^3 / 2.1 x 10^3 Kilometers/Mintues.

User Pavel Linkesch
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22 votes
22 votes

Answer:

Part a =

The distance between Earth and the moon is 3.8 x 10^5 kilometers. The time taken to travel this distance was 2.16 x 10^3 minutes.

The formula to calculate speed is speed = distance/time.

So, the speed of Luna I was 3.8 x 10^5/2.16 x 10^3 kilometers/meters.

Part b =

The expression from part A is 3.8 x 10^5/2.16 x 10^3 kilometers/meters. Break the expression into the product of two fractions, one fraction for the first factors and the other for the powers of 10.

3.8/2.16 x 10^5/10^3

Part c =

3.8/2.16 x 10^5/10^3

Using division, the value of the first fraction is 3.8/2.16 = 1.759 = 1.76.

Using the properties of exponents, the value of the second fraction is 10^5/10^3 = 10^5 x 10^-3 = 10^ 5 - 3 = 10^2.

3.8/2.16 x 10^5.10^3 = 1.76 x 10^2

Part d =

The value 1.76 x 10^2 is written in scientific notation. So, the average speed of Luna I was 1.76 x 10^2 kilometers/minute.

Explanation:

Answer in bold. All edmentum answers :)

User Bitkid
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